নিচের অপশন গুলা দেখুন
1 উত্তর
সঠিক উত্তর হচ্ছে:
ব্যাখ্যা:
$$\eqalign{
& {\text{sin}}\left( {2x - {{20}^ \circ }} \right) = {\text{cos}}\left( {2y + {{20}^ \circ }} \right) \cr
& \Rightarrow \left( {2x - {{20}^ \circ }} \right) + \left( {2y + {{20}^ \circ }} \right) = {90^ \circ } \cr
& \left[ {{\text{If sin A}} = {\text{cos B, then A}} + {\text{B}} = {{90}^ \circ }} \right] \cr
& \Rightarrow 2\left( {x + y} \right) = {90^ \circ } \cr
& \Rightarrow x + y = {45^ \circ } \cr
& \therefore \tan \left( {x + y} \right) \cr
& = \tan {45^ \circ } \cr
& = 1 \cr} $$