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Getting at most Two heads means 0 to 2 but not more than 2Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}Let E = event of getting at most two headsThen E = {TTT, TTH, THT, HTT, THH, HTH, HHT}∴ P(E) = n(E)/n(S) = 7/8
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